# A drive-through at a Fast Food serves 300 customers over a 10-hour day. On average, a customer

A drive-through at a Fast Food serves 300 customers over a 10-hour day. On average, a customer spends 2 minutes waiting in line, 3 minutes placing the order, and 5 minutes completing the order before leaving the drive-through. How many customers on average are “in” the drive-through (i.e., from the time they enter to the time they exit the drive-through) on a typical day?

a. 30 b.10 c.300 d.5

This problem will be solved using Little’s Law which states:

Rate of arrival x Throughput time = Inventory in the system

Here , Rate of arrival of customers

= 300 customers every 600 minutes ( i.e 10 hours )

= 300 / 600

= 0.5 customers/ minute

Throughput time in the system

= Time for waiting in line + Time for placing the order + Time for completing the order

= 2 + 3 + 5

= 10 minutes

Hence,

Number of customers in the Drive through on a typical day ( i.e. inventory of the system)

= Rate of arrival of customers x Throughput time in the system

= 0.5 x 10

= 5

 NUMBER OF CUSTOMERS ON AVERAGE ARE IN THE DRIVE THROUGH = 5
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