# Answered Essay: A solution is found to be 0.0678% by weight FeCl2. What is the concentration of the Cl1- ion

A solution is found to be 0.0678% by weight FeCl2. What is the concentration of the Cl1- ion expressed in ppm?

Molar mass of FeCl2 = 126.751 g/mol
Assume that 0.0678 g of FeCl2 present in 100 grams of solution and that the density is 1 g/ml, so it is100 mL of solution.
So, the weight of water = 100-.0.0678 = 99.9322 g H2O

.Number of moles of FeCl2 = 0.0678 g/ 126.751 g/mol = 5.35 x 10-4 moles of FeCl2

5.35 x 10-4 moles of FeCl2$\equiv$ 2 x 5.35 x 10-4 moles of of Cl ions = 1.07 x 10-3 moles of Cl ions​

1.07 x 10-3 moles of Cl ions​ = 1.07 x 10-3 x 35.5 g of Cl ions = 0.038 g Cl ions

0.038 g Cl ions = 38 mg Cl ions

Concentration of Cl ion in the solution, C = m/v where m is the mass of Cl ions in mg and v is in L because it is ppm
C = 38 mg / 0.1 L = 380 ppm

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