Consider a general reaction
A(aq) rightwardsharpoonoverleftwardsharpoon B(aq) The delta G^ of the reaction is -7.410 kJ middot mol^-1. Calculate the equilibrium constant for the reaction. (Assume a temperature of 25 degree C.) K’_eq = What is delta G at body temperature (37.0 degree C) if the concentration of A is 1.6 M and the concentration of B is 0.45 M? delta G = Use the equation delta G degree = – RT ln(K’_eq) which is rearranged as K’_eq = e^-delta G degree/RT Alternatively, delta G degree = -2.303 RT log(K’_eq) Or, if using the alternative equation, K’_eq = 10 ^-delta G degree /10^2.3.3 RT Where R is the gas constant (8.314 J middot mol^-1 middot K^-1) and T is the temperature in kelvins. Note that the temperature under standard conditions is 25 degree C.