Ans. #1. See the figure.
#2. See the balanced reaction, 1 mol acetyl salicylic acid reacts with 2 mol methanol to produce a mol each of methyl salicylate, methyl acetate and water.
Theoretical molar ration of reactants is- acetyl salicylic acid : methanol = 1 : 2
Moles of acetyl salicylic acid = 5.56 millimoles
Mole of methanol = 86.51 millimoles
Experimental molar ration of reactants is- acetyl salicylic acid : methanol
= 5.56 : 86.51 = 1 : 15.56
Compare the theoretical and experimental molar ratio of reactants, methanol is present is excess. Thus, acetyl salicylic acid is the limiting reactant.
#3. A. See the balanced reaction, 1 mol acetyl salicylic acid produces 1 mol methyl salicylate.
Theoretically, 5.56 mmol acetyl salicylic acid shall produce 5.56 mmoles of methyl salicylate, too.
Theoretical moles of methyl salicylate produced = 5.56 mmoles = 0.00556 moles
Theoretical yield = Theoretical moles produced x molar mass
= 0.00556 mol x (152.15 g/mol)
= 0.846 g
#3.B. % yield = (Actual yield/ Theoretical yield) x 100
= (Actual yield/ 0.846 g) x 100
Put the actual yield (mass) you obtained experimentally in above reaction to get the exact value.