Answered Essay: C++ programming

C++ programming

A rectangle is completely determined by the coordinates of two of its diagonally opposite corners. For example, the points (1, 2) and (7, 5) determine a rectangle whose left edge has equation x = 1, whose right edge has equation x = 7, whose bottom edge has equation y = 2 and whose top edge has equation y = 5. Any point whose x-coordinate is between 1 and 7 and whose y-coordinate is between 2 and 5 lies within this rectangle.

Write a program that determines whether or not a given point is contained in a given rectangle.

Your program should:

Prompt the user for the upper left corner of a rectangle.

Prompt the user for the lower right corner of the rectangle.

Prompt the user for the coordinates of a point.

Output whether or not the point is inside the rectangle.

Repeat the above steps until the user enters (0, 0) for both corners of the rectangle.

Assume that all coordinates are non-negative integers with (0, 0) being the extreme upper-right corner.

Be readable with appropriate documentation and formatting.

Expert Answer

 

here i have written the C++ program as per the requirement.

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Note: Please note that the below program has been tested on ubuntu 16.04 system and compiled under gcc compiler. This code will also work on other IDE’s.

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Program:

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//Header file declration

#include<iostream>

#include<stdlib.h>

//Namespsce declration

using namespace std;

//start of main function

int main()

{

//variable data type declration

int x_left, x_right, y_upper, y_lower;

int x, y;

//input left corner

cout<<“Enter the upper left corner: “;

cin>>x_left>>y_upper;

//input right corner

cout<<“Enter the lower right corner: “;

cin>>x_right>>y_lower;

//start of do while loop

do
{

//enter the coordinates

cout<<“Enter the cordinates of a point: “;

cin>>x>>y;

//check if the points lies inside the ranctangle

if((x > x_left && x < x_right ) && (y > y_lower && y < y_upper))

{

cout<<“Points “<<x<<” , “<<y<<” lies inside the rectangle.”<<endl;

}

//if points are 0, 0 then terminate the program

else if(x == 0 && y == 0)

{

break;

}

//else points are not inside the ractangle

else

{

cout<<“Points “<<x<<” , “<<y<<” do not lies inside the rectangle.”<<endl;

}

}while(x != 0 && y != 0);

return 0;

}//end of the program

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here i have attached a sample run of the program as a screen shot…

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Output:

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