Answered Essay: Consider a process consisting of five resources that are operated eight hours per

Consider a process consisting of five resources that are operated eight hours per day. The process works on three different products, A, B, and C Number Processing Process ing Processing Resource time for A workers (minutes) (minutes) time for C (minutes) time for B 2 2 4 15 2 4 0 2 4 Demand for the three different products is as follows: product A, 40 units per day; product B, 50 units per day; and product C, 60 units per day a. What is the bottleneck? Resource 1 O O Resource 2 Resource 3 Resource 4 O Resource 5 What is the flow rate for Flow A assuming that demand must be served in the mix C)? What is the flow rate for Flow B assuming that demand must be served in the mix C)? What is the flow rate for Flow C assuming that demand must be served in the mix C)? b. described above (i.e., for every four units of A, there are five units of B and six units of units per day c. described above (i.e., for every four units of A, there are five units of B and six units of units per day d. described above (i.e., for every four units of A, there are five units of B and six units of units per dayPlease show me how to solve this problem with steps and methods

Consider a process consisting of five resources that are operated eight hours per day. The process works on three different products, A, B, and C. Demand for the three different products is as follows: product A, 40 units per day: product B, 50 units per day: and product C, 60 units per day. a. What is the bottleneck? Resource 1 Resource 2 Resource 3 Resource 4 Resource 5 What is the flow rate for Flow A assuming that demand must be served in the mix described above (i.e., for every four units of A, there are five units of B and six units of C)? units per day c. What is the flow rate for Flow B assuming that demand must be served in the mix described above (i.e., for every four units of A, there are five units of B and six units of C)? units per day d. What is the flow rate for Flow C assuming that demand must be served in the mix described above (i.e., for every four units of A, there are five units of B and six units of units per day C)? units per day

Expert Answer

Answer
Resource Number of workers Total minutes available Processing time for A (minutes) Processing time for B (minutes) Processing time for C (minutes)
1 2 960 5 5 5
2 2 960 4 4 5
3 1 480 15 0 0
4 1 480 0 3 3
5 2 960 6 6 4
Total 30 18 17
Demand per day 40 50 60
Resource Number of workers Time available
(minutes )
time required to meet demand
(minutes)
Total time required (minutes) Difference – Available – Required time (minutes)
Product A Product B Product C
1 2 960 200 250 300 750 210
2 2 960 160 200 300 660 300
3 1 480 600 0 0 600 -120
4 1 480 0 150 180 330 150
5 2 960 240 300 240 780 180
Total 1200 900 1020
time required per unit 30 18 17
b. Flow rate for A (number of units produced in the mix when 1 unit of A is produced) 1 0.6 0.57
c. Flow rate for B (number of units produced in the mix when 1 unit of B is produced) 0.6 1 0.94
d. Flow rate for C (number of units produced in the mix when 1 unit of C is produced) 0.57 0.94 1.00

a. Resource 3 is the bottleneck since the Required time is in excess of the available time, therefore, causing wait time for the subsequent process steps

formula table

Resource Number of workers Total minutes available Processing time for A (minutes) Processing time for B (minutes) Processing time for C (minutes)
1 2 =+B2*8*60 5 5 5
2 2 =+B3*8*60 4 4 5
3 1 =+B4*8*60 15 0 0
4 1 =+B5*8*60 0 3 3
5 2 =+B6*8*60 6 6 4
Total =SUM(D2:D6) =SUM(E2:E6) =SUM(F2:F6)
Demand per day 40 50 60
Resource Number of workers Time available
(minutes )
time required to meet demand
(minutes)
Total time required (minutes) Difference – Available – Required time (minutes)
Product A Product B Product C
1 2 =+B13*8*60 =+$D$9*D2 =+$E$9*E2 =+$F$9*F2 =SUM(D13:F13) =+C13-G13
2 2 =+B14*8*60 =+$D$9*D3 =+$E$9*E3 =+$F$9*F3 =SUM(D14:F14) =+C14-G14
3 1 =+B15*8*60 =+$D$9*D4 =+$E$9*E4 =+$F$9*F4 =SUM(D15:F15) =+C15-G15
4 1 =+B16*8*60 =+$D$9*D5 =+$E$9*E5 =+$F$9*F5 =SUM(D16:F16) =+C16-G16
5 2 =+B17*8*60 =+$D$9*D6 =+$E$9*E6 =+$F$9*F6 =SUM(D17:F17) =+C17-G17
Total =SUM(D13:D17) =SUM(E13:E17) =SUM(F13:F17)
time required per unit 30 18 17
b. Flow rate for A (number of units produced in the mix when 1 unit of A is produced) =D19/30 =+E19/D19 =+F19/D19
c. Flow rate for B (number of units produced in the mix when 1 unit of B is produced) =+E19/D19 =+E19/18 =+F19/E19
d. Flow rate for C (number of units produced in the mix when 1 unit of C is produced) =+F19/D19 =+F19/E19 =+F19/F19
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