Answered Essay: estion 1 (5 points) 17.1 g of calcium chloride is dissolved in 750, mL of a water (d =

estion 1 (5 points) 17.1 g of calcium chloride is dissolved in 750, mL of a water (d = 1.00 g/mL) and is placed in the freezer at -2 °C overnight. Which statement best describes what would happen to the solution? O a The freezing point of the calcium chloride solution would be -1.15 C, so the solution would freeze. h The freezing point of the calcium chloride solution would be b) -0.382°C, so the solution would freeze. e) The freezing coint of the calcum chloride solution would be 1.15 c, so the solution would freeze Save 9/6/2017
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estion 1 (5 points) 17.1 g of calcium chloride is dissolved in 750, mL of a water (d = 1.00 g/mL) and is placed in the freezer at -2 °C overnight. Which statement best describes what would happen to the solution? O a The freezing point of the calcium chloride solution would be -1.15 C, so the solution would freeze. h The freezing point of the calcium chloride solution would be b) -0.382°C, so the solution would freeze. e) The freezing coint of the calcum chloride solution would be 1.15 c, so the solution would freeze Save 9/6/2017

Expert Answer

1)

Molar mass of CaCl2,

MM = 1*MM(Ca) + 2*MM(Cl)

= 1*40.08 + 2*35.45

= 110.98 g/mol

mass(CaCl2)= 17.1 g

number of mol of CaCl2,

n = mass of CaCl2/molar mass of CaCl2

=(17.1 g)/(110.98 g/mol)

= 0.1541 mol

m(solvent)= 750 g

= 0.75 Kg

Molality,

m = number of mol / mass of solvent in Kg

=(0.1541 mol)/(0.75 Kg)

= 0.2054 molal

i for CaCl2 is 3

use:

Δ Tf = i*Kf*mb

Δ Tf = 3.0*1.86 oC/m * 0.2054 m

Δ Tf = 1.15 oC

So, freezing point is -1.15 oC

Since temperature is less than -1.15 oC, it will freeze

Answer: a

I am allowed to answer only 1 question at a time

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