Answered Essay: Historical demand for a product is: a. Using a weighted moving average with weights of 0.40

Historical demand for a product is: a. Using a weighted moving average with weights of 0.40 (June), 0.20 (May), and 0.40 (April), find the July forecast. (Round your answer to 1 decimal place.) July forecast b. Using a simple three-month moving average, find the July forecast. (Round your answer to 1 decimal place.) July forecast c. Using single exponential smoothing with alpha = 0.20 and a June forecast = 12, find the July forecast. (Round your answer to 1 decimal place.) July forecast d. Using simple linear regression analysis, calculate the regression equation for the preceding demand data. (Do not round intermediate calculations. Round your intercept value to 1 decimal place and slope value to 2 decimal places.) Y = + t e. Using the regression equation in d, calculate the forecast for July. (Do not round intermediate calculations. Round your answer to 1 decimal place.) July forecast

Expert Answer

Answer:- Weighted moving average ; –

Forecast for July = (14*0.4 + 15*0.2+13*0.4)/(0.4+0.2+0.4) = (5.6+3+5.2)/1

Forecast for July =13.8

Answer:- Simple three-month moving average:-

Forecast for July =(14+15+13)/2=14

Answer:-

Month	Demand
Jan	13
Feb	10
March	14
April	13
May	15
June	14

Month (X)	Number of Accident(Y)	X*Y	X*X
1	13	13	1
2	10	20	4
3	14	42	9
4	13	52	16
5	15	75	25
6	14	84	36
∑X = 21	∑Y = 79	∑XY = 286	∑X^2 =91

Slope(b) = (N∑XY – (∑X)(∑Y)) / (N∑X² – (∑X)²)
Slope B = (6286 – 2179)/(6*91-21^2)
B = 0.543

Intercept(a) = (∑Y – b(∑X)) / N
a=(79-0.543*21)/6
a=11.27

Regression Equation(y) = a + bx
y=11.27+0.543*x

Forecast for July
y=11.27+0.543*7
y=15.071

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