Answered Essay: In an article in the Journal of Advertising, Weinberger and Spotts compare the use of humor in

In an article in the Journal of Advertising, Weinberger and Spotts compare the use of humor in television ads in the United States and the United Kingdom. They found that a substantially greater percentage of U.K. ads use humor. (a) Suppose that a random sample of 374 television ads in the United Kingdom reveals that 137 of these ads use humor. Find a point estimate of and a 95 percent confidence interval for the proportion of all U.K. television ads that use humor. (Round your answers to 3 decimal places.) The 95 percent confidence interval is (b) Suppose a random sample of 455 television ads in the United States reveals that 113 of these ads use humor. Find a point estimate of and a 95 percent confidence interval for the proportion of all U.S. television ads that use humor. (Round your answers to 3 decimal places.) The 95 percent confidence interval is[ (c) Do the confidence intervals you computed in parts a and b suggest that a greater percentage of U.K. ads use humor? (Click to select)the U.K. 95 percent confidence interval is (Click to selectthe maximum value in the confidence interval for the U.S

In an article in the Journal of Advertising, Weinberger and Spotts compare the use of humor in television ads in the United States and the United Kingdom. They found that a substantially greater percentage of U.K. ads use humor. (a) Suppose that a random sample of 374 television ads in the United Kingdom reveals that 137 of these ads use humor. Find a point estimate of and a 95 percent confidence interval for the proportion of all U.K. television ads that use humor. (Round your answers to 3 decimal places.) The 95 percent confidence interval is (b) Suppose a random sample of 455 television ads in the United States reveals that 113 of these ads use humor. Find a point estimate of and a 95 percent confidence interval for the proportion of all U.S. television ads that use humor. (Round your answers to 3 decimal places.) p = The 95 percent confidence interval is (c) Do the confidence intervals you computed in parts a and b suggest that a greater percentage of U.K. ads use humor? the U.K. 95 percent confidence interval is the maximum value in the confidence interval for the U.S.

Expert Answer

Answer

(a)

Zα/2 = NORMSINV(1 – 0.025) = 1.96
Point estimate = p = 137/374 = 0.366
Std. Error = sqrt(p*(1 – p)/n) = sqrt(0.366*(1-0.366)/374) = 0.0249

Conf. interval = [0.366 – 1.96*0.0249, 0.366 + 1.96*0.0249] = [0.317, 0.415]

(b)

Zα/2 = NORMSINV(1 – 0.025) = 1.96
Point estimate = p = 113/455 = 0.248
Std. Error = sqrt(p*(1 – p)/n) = sqrt(0.248*(1-0.248)/455) = 0.0203

Conf. interval = [0.248 – 1.96*0.0203, 0.248 + 1.96*0.0203] = [0.209, 0.288]

(c)

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