Answered Essay: Open an editor of your choice and type in the following Java program shell: public class Lab3 { public static void main(String[] arg

1. Open an editor of your choice and type in the following Java program shell public class Lab3 public static void main (Stringl args) i 2. Declare two local variables inside the main method of type float called fahrenheit and another called centigrade. Compile the program (making sure, of course, that it compiled with no errors.) 3. Write a statement to assign farenheit a value of 98.6 4. The formula to convert Fahrenheit to Centigrade is C5/9 (f-32) Code this statement in your program. Provide output statements that display to the console what Fahrenheit and converted centigrade degrees are 5. Now put in a for loop that will print the centigrade values of the numbers 0.0, 5.0, 10.0, 15.0, , 40.0 6. After the for loop, put in a while loop that does the same output as part 5.

Open an editor of your choice and type in the following Java program shell: public class Lab3 { public static void main(String[] args) { } } Declare two local variables inside the main method of type float called fahrenheit and another called centigrade. Compile the program (making sure, of course, that it compiled with no errors.) Write a statement to assign farenheit a value of 98.6 The formula to convert Fahrenheit to Centigrade is c = 5/9 (f – 32) Code this statement in your program. Provide output statements that display to the console what Fahrenheit and converted centigrade degrees are. Now put in a for loop that will print the centigrade values of the numbers 0.0, 5.0, 10.0, 15.0, , 40.0 After the for loop, put in a while loop that does the same output as part 5.

Expert Answer

 

public class Lab3 {
public static void main(String[] args){
float fahrenheit,centigrade;
fahrenheit=98.6f;

centigrade=((float)5/9)*(fahrenheit-32);
System.out.println(“Centigrade value for “+fahrenheit+” Fahrenheit temperature is :”+centigrade);

for(int i=0;i<=40;i=i+5){
System.out.println(i+” Centigrade Temperature”);
}
int i=0;
while(i<=40){
System.out.println(i+” Centigrade Temperature”);
i=i+5;
}

}
}

OUTPUT:

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