Answered Essay: Ross Hopkins, president of Hopkins Hospitality, has developed the tasks, durations, and

Ross Hopkins, president of Hopkins Hospitality, has developed the tasks, durations, and predecessor relationships in the tollowing table tor building new motels. Time (weeks) Immediate Time (weeks) Immediate Activity a b Predecessor(s)Activity a 10 23 16 10 bPredecessor(s) C, E 14 4 12 D, G, H 20 C, E a) The expected (estimated) time for activity C is 13.3 weeks. Round your response to two decimal places.) b) The variance for activity C is 1.78 weeks. (Round your response to two decimal places.) c) Based on the calculation of the estimated times, the critical path is A-C-F-H -J -K d) The estimated time for the critical path is 40.99 weeks. (Round your response to two decimal places.) e) The activity variance along the critical path is 11.06 weeks. (Round your response to two decimal places.) f) The probability that Hopkins Hospitality will finish the project in 42 weeks or less is (Enter as a probability and round your response to three decimal places.)

Ross Hopkins, president of Hopkins Hospitality, has developed the tasks, durations, and predecessor relationships in the following table tor building new motels. a) The expected (estimated) time for activity C is 13.3 weeks. (Round your response to two decimal places.) b) The variance for activity C is 1.78 weeks. (Round your response to two decimal places.) c) Based on the calculation of the estimated times, the critical path is A-C-F-H -J – K. d) The estimated time for the critical path is 40.99 weeks. (Round your response to two decimal places.) e) The activity variance along the critical path is 11.06 weeks. (Round your response to two decimal places.) f) The probability that Hopkins Hospitality will finish the project in 42 weeks or less is .(Enter as a probability and round your response to three decimal places.)

Expert Answer

Answer

I presume that we have to answer to question #f only .

Accordingly please find below answer to question #f :

The activity variance along the critical path = 11.06 weeks

Therefore,

Standard deviation of the critical path

= Square root ( activity variance of critical path)

= Square root ( 11.06)

= 3.325 weeks

Let the Z value for the corresponding probability that the project will finish in 42 weeks = Z1

Then,

Estimated time for the critical path + Z1 x Standard deviation of duration of the critical path = 42

Or, 40.99 weeks + Z1 x 3.325 weeks = 42 weeks

Or, 3.325.Z1 = 42 – 40.99 = 1.01

Or, Z1 = 1.01 / 3.325 = 0.3037

The corresponding probability as derived from standard normal distribution table for Z = 0.3037 ( or 0.30 rounded to 2 decimal places ) will be equal to 0.61791 ( or 0.618 rounded to three decimal places)

THE PROBABILITY THAT HOPKINS HOSPITALITY WILL FINISH THE PROJECT IN 42 WEEKS OR LESS IS 0.618
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