Answered Essay: This is my answer. But it is incorrect. Could you help to revise that ?

Explanation::

• As in the provided code we do not prompt user to enter string and charater, instead we directly hard code and initialize the variables userInput and firstLetter in code itself.
• So when I did so I got correct output.
• The only change I made is in if statement.
• See the code provided below.

Code in java:

import java.util.Scanner;

public class CharMatching{

public static void main(String[] args){

String userInput=””;

char firstLetter=’-‘;

userInput=”1,2,Buckl my shoe.”;

firstLetter=’1’;

/*

* In if condition below I have changed from ‘b’ to variable name

* firstLetter that stores first character to be checked.

*/

if(userInput.charAt(0)==firstLetter){

System.out.println(“Found match: “+firstLetter);

}else{

System.out.println(“No match:”+firstLetter);

}

return;

}

}

Output::

Another version of code in java where user is asked to enter userInput string and firstLetter character::

Code in java::

import java.util.Scanner;

public class CharMatching{

public static void main(String[] args){

Scanner sc=new Scanner(System.in);

String userInput=””;

char firstLetter=’-‘;

System.out.println(“nEnter the string as userInput::”);

userInput=sc.nextLine();

System.out.println(“nEnter the character as firstLetter::”);

firstLetter=sc.next().charAt(0);;

if(userInput.charAt(0)==firstLetter){

System.out.println(“Found match: “+firstLetter);

}else{

System.out.println(“No match:”+firstLetter);

}

return;

}

}

Output::

Test case 1::

Test case 2::

Test case 3::

Thank you!!