Answered Essay: This problem is supposed to be coded in Standard ML, I tried this

1. exists -15% This function should return true if the first argument is a member of the second argument and have type (aa list) ->bool. Explain in a comment why the typeis (aa list) ->bool and not (aa list) bool Note: this function is not required to be tail-recursive. Examples exists (1,1) false > exists (1,(1,2,31) true exists ((1],1]1) true > exists ((1), [[3),[5]]); false exists c,b,c,z]): true

This problem is supposed to be coded in Standard ML, I tried this

fun exists (x, L) = if null L then false else if x = hd(L) then true else exists(x, tl(L));

but I get this error ‘stdIn:27.52 Warning: calling polyEqual’.

1. exists -15% This function should return true if the first argument is a member of the second argument and have type (”a”a list) ->bool. Explain in a comment why the typeis (”a”a list) ->bool and not (‘a’a list) bool Note: this function is not required to be tail-recursive. Examples exists (1,1) false > exists (1,(1,2,31) true exists ((1],1]1) true > exists ((1), [[3),[5]]); false exists “c”,”b”,”c”,”z”]): true

Expert Answer

 

Hi,
You are going in the right direction,
here is the code, that will work with the same logic as yours
fun exists_in (item: ”int, mylist:”list) =
if null mylist //null check
then false
else if (hd mylist) = item // hd list gives first items
then true
else exists_in(item, tl mylist) // tl gives all but 1st element
exists_in(1,[1,2,3]);
Thumbs up if this was helpful, otherwise let me know in comments. Good Day.

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