Solved Homework: Question: Ask user to enter your student candidate number, calculate the sum of the digits. If the sum is l…

Using C language.

Ask user to enter your student candidate number, calculate the sum of the digits. If the sum is less than 20, display the sum to the power of 2, otherwise display the square root of the sum. If the sum equals to 25, display this sum as well. (15 Marks)

Ask user to enter your student candidate number, calculate the sum of the digits. If the sum is less than 20, display the sum to the power of 2, otherwise display the square root of the sum. If the sum equals to 25, display this sum as well. (15 Marks)

Expert Answer

answers

Below is your code.. This can take candidate id of very long length because I am using long long int. Let me know if you have any issues: –

#include

#include

void main() {

long long int candId, digit, sum = 0;

printf(“Enter the candidate number: “);

scanf(“%ld”, &candId);

while (candId > 0)

{

digit = candId % 10;

sum = sum + digit;

candId /= 10;

}

if (sum < 20) {

printf(“Sum to the power of 2 = %lldn”,(int)pow(sum,2));

} else {

printf(“Square root of the sum = %fn”,sqrt(sum));

if(sum == 25) {

printf(“Sum of digits = %lldn”,sum);

}

}

}

Output

sumOfDigits.c 1 2 #include« stdio.h» #include<math.h» DAcheggC++120091sumOfDigits.exe Enter the candidate nunber: 3232323232 Square root of the sun 5.000000 Sum of digits 25 4 void main() { long long int candId, digit, sum0 printf(Enter the candidate number)5 scanf(ld &candId)j while (candId> e) 7 8 Process exited af ter 3.003 seconds with returnvalue 20 Press any key to continue . . - 10 digit candid % 10; sum = sum + digit; candId /-10; 12 13 if (sum 20) 15 16 17 18 19 20 21 printf( Sum to the power of 2-%11dn, (int)pon(sum,2)); else printf(Square root of the sum if(sum25) %fn, sqrt (sum)); printf( Sum of digits-%11dn, sum);

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