Solved Homework: Question: Create an application that calculates the area and perimeter of a rectangle and validates the use…

Please find below the code which handles all the scenarios. Also I have provided the logic in separate methods and comments. Hope you receive a full credit.

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package com.assignment.distributedComputing;

import java.util.*;

public class JavaAreaAndPerimeterOfRectangle {

public static void main(String args[]) {

//variable declaration

int length = 0, width=0, area=0, perimeter=0;

boolean flag=false; //flag variable to determine continue/exit choice from user

System.out.println(“Welcome to the My Calculator Application”);

do{

//initialize scanner

Scanner s = new Scanner(System.in);

while(true){

System.out.println(“Enter Length”);

String str = s.next(); //take user input

try{

length = Integer.parseInt(str); //convert the user input to integer from string

if(length > 1000000){ //check if lenght is greater than 1000000

System.out.println(“Error! Number must be less than 1000000.0”);

}

else if (length<=0){ //check if length is negative

System.out.println(“Error! Number must be greater than 0.0”);

}

else{ // break the loop – meaning the length is correctly entered by user

break;

}

}catch (NumberFormatException ex) { // If user types wrong input

System.out.println(“Error! Invalid decimal value. Try again.”);

}

}

while(true){

System.out.println(“Enter Width :”);

String str = s.next();

try{

width = Integer.parseInt(str);

if(width > 1000000){ //check if lenght is greater than 1000000

System.out.println(“Error! Number must be less than 1000000.0”);

}

else if (width<=0){ //check if length is negative

System.out.println(“Error! Number must be greater than 0.0”);

}

else{ // break the loop – meaning the width is correctly entered by user

break;

}

}catch (NumberFormatException ex) {// If user types wrong input

System.out.println(“Error! Invalid decimal value. Try again.”);

}

}

findArea(length,width); //call method to print area

findPeremeter(length,width); //call method to print peremeter

while(true){

System.out.println(“Continue? (y/n)”); //ask user to enter choice y/n

String str = s.next();

if (str.equals(“n”)){ //if user enters n then we should terminate the program

flag = true; //set the flag to true

break;

}

else if(str.equals(“y”)){ //if user wants to continue

break;

}

else{ //if user enters some other characters

System.out.println(“Error! Entry must be ‘y’ or ‘n’. Try again.”);

}

}

}while(flag!=true);

}

//method to print parameter

private static void findPeremeter(int length, int width) {

System.out.println(“perimeter :”+ 2 * (length + width));

}

//method to print area

private static void findArea(int length, int width) {

System.out.println(“Area :”+ length * width);

}

}

Sample Output :

Welcome to the My Calculator Application

Enter length: ten

Error! Invalid decimal value. Try again.

Enter length: -10

Error! Number must be greater than 0.0

Enter length: 100000000000000000000000

Error! Number must be less than 1000000.0

Enter length: 100

Enter width: what?

Error! Invalid decimal value. Try again.

Enter width: 0

Error! Number must be greater than 0.0

Enter width: 10000000000000000000000

Error! Number must be less than 1000000.0

Enter width: 100

Area:         10000.0

Perimeter:    400.0

Continue? (y/n): x

Error! Entry must be ‘y’ or ‘n’. Try again.

Continue? (y/n): n

Happy Learning 🙂