Solved Homework: Question: Write a Program to determine a city's Hurricane Vulnerability Level (HVL). (60 points) Miami, Flo…

No language mentioned so I did it in C++

Explanation in comments

#include <bits/stdc++.h>

using namespace std;

int main() {

// your code goes here

//take input city_name,total_population,total_area,wind_speed

string city_name;

int total_population,total_area,wind_speed;

//taking input

cin>>city_name>>total_population>>total_area>>wind_speed;

//calculate population density

int population_density=total_population/total_area;

//if population density is greater than 11000 and wind speed is greater than 111

//print HVL very high

if(population_density>=11000&&wind_speed>=111)

{

cout<<“Population density of “<<city_name<<” is “<<population_density<<” and its hurricane vulnerabilty level(HVL) is VERY HIGH”<<endl;

}

//in all other cases

else

{

//if wind_speed<74 HVL is low

if(wind_speed<74)

cout<<“Population density of “<<city_name<<” is “<<population_density<<” and its hurricane vulnerabilty level(HVL) is LOW”<<endl;

//according to table in this case HVL is moderate

if(wind_speed>=74&&wind_speed<=95)

cout<<“Population density of “<<city_name<<” is “<<population_density<<” and its hurricane vulnerabilty level(HVL) is MODERATE”<<endl;

//In this case also HVL is moderate

if(wind_speed>=96&&wind_speed<=110)

cout<<“Population density of “<<city_name<<” is “<<population_density<<” and its hurricane vulnerabilty level(HVL) is MODERATE”<<endl;

//In all other cases HVL is high

else

cout<<“Population density of “<<city_name<<” is “<<population_density<<” and its hurricane vulnerabilty level(HVL) is HIGH”<<endl;

}

return 0;

}