# Solved Homework: Question: Write a recursive method that counts the number of mines on a grid. A mine is defined as a contig…

Write a recursive method that counts the number of mines on a grid. A mine is defined as a contiguous collection of X’s (connected horizontally and vertically). In java language

Input

Max dimensions of the array

Distribution of mines on the array

Output

The number of mines and the layout of the grid showing the locations of the mines.

Requirements checklist:

❑ Documented source code (include any assumptions you make)

Input File (in.txt)

The format of the input file is as follows: First line is the dimensions of the grid.. Then the grid containing 1s for the creatures and 0s for the spaces. The file terminates by 0 0.

5 5

…..

.XXX.

…..

…..

…..

5 5

….X

.XXX.

X….

…..

…..

0 0

Output File (out.txt)

Experiment # 1

Number of Mines: 1

0 0 0 0 0

0 1 1 1 0

0 0 0 0 0

0 0 0 0 0

0 0 0 0 0

Experiment #2

Number of Mines: 3

0 0 0 0 1

0 2 2 2 0

3 0 0 0 0

0 0 0 0 0

0 0 0 0 0

Marking Scheme

Out of

Documentation

3

Meaningful variable names

2

Correct input format

2

Correct output format

2

Modularity

4

Tested

12

Total

25

import java.io.File;

import java.io.FileNotFoundException;

import java.io.FileWriter;

import java.io.IOException;

import java.util.Scanner;

public class Mine {

public static void main(String[] args) throws IOException {

File file =

new File(“D:\mine.txt”);

Scanner sc = null;

//For writing

FileWriter writer =null;

try {

//To scan the file

writer = new FileWriter(“D:\out.txt”, true);

sc = new Scanner(file);

} catch (Exception e) {

e.printStackTrace();

}

int l=0;

while(sc.hasNextLine()){

l++;

int m=0;

String[] data=sc.nextLine().split(” “);

int row=Integer.parseInt(data[0]);

int col=Integer.parseInt(data[1]);

int [][] result=new int[row][col];

int i=0,j=0;

while(i<row){

j=0;

boolean flag=true;

String line=sc.nextLine();

while(j<col){

char value=line.charAt(j);

if(value==’X’){

if(flag){

m++;

flag=false;

}

result[i][j]=m;

}else{

result[i][j]=0;

}

j++;

}

i++;

}

//writing in out.txt if row > 0

if(row!=0){

writer.write(“Experiment # “+l);

writer.write(“rn”);

writer.write(“Number of Mines:”+m);

writer.write(“rn”);

for(int temp[]:result){

for(int temp1:temp){

writer.write(temp1+” “);

}

writer.write(“rn”);

}

}

}

writer.close();

}

}

Pages (550 words)
Approximate price: -

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